5moles of PCl5 are heated ina closed vessel of 5litres capacity.At equilibrium 40% of PCl5 is found to be dissociated.What is the value of K_c?
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The reaction is PCl5 → PCl3 + Cl2
The initial number of moles = 5
coefficient of dissociation = 0.4
No. of moles of PCl5 left = 5 - 5*0.4 = 3
No. of moles of PCl3 = No. of moles of Cl2 = 5*0.4 = 4
Kc = 2*2/3 = 4/3 = 1.33
The initial number of moles = 5
coefficient of dissociation = 0.4
No. of moles of PCl5 left = 5 - 5*0.4 = 3
No. of moles of PCl3 = No. of moles of Cl2 = 5*0.4 = 4
Kc = 2*2/3 = 4/3 = 1.33
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