If A B C are positive acute angle and sin (B+C-A)=cos (C+A-B)=tan (A+B-C)=1 then A B C are
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The sum of 3 angles of a triangle is 180° .
So , A+B+C=180 .
This implies that A+B-C=180-2C
Sin(180-2C)=Sin2C=(√3)/2 .
As we know that Sin60°=(√3)/2 . Also sin120°=√3/2 . Thus ,
C=30° or C=60° .
So , A+B+C=180 .
This implies that A+B-C=180-2C
Sin(180-2C)=Sin2C=(√3)/2 .
As we know that Sin60°=(√3)/2 . Also sin120°=√3/2 . Thus ,
C=30° or C=60° .
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