6! (1.3.5 ..... 11) 2^6.
find the value of
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Answered by
5
Answer:
kiski value nikale bhai........
mehak432:
it's answer is 12! but how
u haven't ask the value of anything,then 12 is the answer of what?????
it is the question of permutation
hmm right
please send sol step by step
ookk
Answered by
6
Step-by-step explanation:
(720)*(10395)*(64) = 479001600
= (6!) x {(12)!/2x(6!) } x (2^6)
= 32 x (12)!
= (2^5) x (12)!
1.3.5.7.9....(2n-1)
= 1.2.3.4.5....(2n-1)(2n) / (2.4.6.8.10.....2n)
= 2n factorial / 2 *( 1.2.3.4.....n)
= 2n factorial / 2* n factorial
I am not ask you this question
what ????
please see question again
ya u r wrong bro
yess I see once more again this question
then give answer
okkk wait
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