Question

6. In an angle ABC, if 3 angleA = 4 angleB = 6 angelC, calculate the angles.

[Hint. Let 3 angleA = 4 angleB = 6 angelC = x. Then, angleA = x/3, angleB = x/4, angleC = x/6] ​

Answer 1

Step-by-step explanation:

x/3+x/4+x/6=4x+3x+2x/12, 9x/12= 180

x= 180×12/9= 240

x=240

angleA= x/3 = 240/3=80°

angleB=x/4 =240/4=60°

angleC=x/6=240/6=40°

Answer 2

The answer:

The angles are 60° , 80° and 40°.

Step-by-step explanation:

By angle sum property,

A + B + C = 180° [Multiple b/s by 6]

2*3*A + 6*B + 6*C = 6*180 [Put values from the question]

2*4*B + 6*B + 4*B = 1080

18B = 1080

B = 60°

A = (4*B)/3 = (4*60)/3 = 80°

C = A/2 = 80/2 = 40°