Question

6.समीकरणो x-y=3और x/3+y/2=6मेxऔरy का मान क्या है
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Answer 1

Answer:

Step-by-step explanation:

x-y=3

x=3+y --eq1.

X/3+y/2=6

(2x+3y)/6=6 (LCM of 3 and 2 is 6)

2x+3y=36

From eq1.

2(3+y)+3y=36

6+2y+3y=36

6+5y=36

5y=36-6

5y=30

y=30/5

y=6

Putting in eq1.

x=3+6

x=9

Hence,x=9&y=6

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Answer 2

Answer:

x=9

y=6

Step-by-step explanation:

given

x-y=3

x/3+y/2=6

now multiply 2nd one with 6 then we get

x/3*6 + y/2*6=6*6

2x+3y=36 -eq1

now multiply x-y with 2

2x-2y=6 -eq2

now subtract eq2 from eq1

2x+3y=36

(-)2x-2y= 6

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0x+5y=30

so we can say 5y=30

hence y=30/5

y=6

from

x-y=3

x-6=3

x=3+6

x=9