Math, asked by taranveer4949, 5 hours ago

6x²+x-1=0
please tell me

Answers

Answered by abhishek4205786
4

Answer:

6x^2 + 3x - 2x -1 = 0

3x(2x+1) -1(2x + 1) = 0

(2x + 1) (3x - 1) = 0

if (2x +1) = 0

then x = -1/2

or

if(3x -1 ) = 0

x = 1/3.

Answered by Anonymous
0

Step-by-step explanation:

6x²+x-1=0

6x² +3x-2x-1 = 0

3x ( 2x-1) - 1(2x-1) = 0

(3x-1)(2x-1) = 0

x = 1or 1/3

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