7.5 g of ethane has how many carbon atoms
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Eth means 2 carbons
7.5g = 7.5 ×2
= 15
Therefore, 15 carbon atoms are present in 7.5g of ethane
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no ofmoles (n)=wt/molecular wt.
n=7.5/30. (30 is molecilar weight of ethane). 23
nxavagadro number(6×10 )×atomicity= no of carbon atoms.
23
no of carbon atoms = 7.5/40×6×10. ×2=3×10power23
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