Question

7
Distance
12, p)
the point
between
locunits
of P Р
ounts (4, 5) and
the value​

Answer 1

Answer:

Solution

The given points are P(-4, 7) and Q(2, -5).

Then, x1=−4,y1=7andx2=2,y2=−5

∴PQ=(x2−x1)2+(y2−y1)2−−−−−−−−−−−−−−−−−−−√

={2−(−4)}2+(−5−7)2−−−−−−−−−−−−−−−−−−−−−−√=62+(−12)2−−−−−−−−−−−√

=36+144−−−−−−−√=180−−−√=36×5−−−−−√=65–√ units