Question

7. The opposite faces of an iron cube are in steam (100°c
and in ice (0°C). Each side of the cube is 2 cm and
thermal conductivity of iron is 0.2 cal s cm°c
How much ice will melt in 5 minutes? Latent head
ice is 80 cal g-1​

Answer 1

Explanation:

$\huge\red{\underline{\underline{\bf Question:-}}}$

The opposite faces of an iron cube are in steam (100°c) and in ice (0°C). Each side of the cube is 2 cm and thermal conductivity of iron is 0.2 cal s cm°c How much ice will melt in 5 minutes? Latent heat ice is 80 cal g-1

$\huge\red{\underline{\underline{\bf Answer:-}}}$

$change \: \: in \: \: temp = \Delta T = (100 - 0) = 100 \\ \\ thermal \: \: conductivity = K = 0.2 \: cal \\ \\ latent \: \: heat = L_{ice} = 80 \: cal {g}^{ - 1}$

$\huge \blue{ Formula..} \\ \\ \boxed{ \frac{mL_{ice}}{\Delta t} = \frac{KA \Delta T}{length} }$

This formula will give us mass of ice melted per minute..

$\implies \frac{m \times \cancel{80}}{ \cancel{60}} = \frac{ \cancel{0.2} \times (2 \times 2) \times 100}{ \cancel{2}} \\ \\ \implies m = \frac{3}{ \cancel4} \times \frac{ \cancel4 \times 10 \cancel{0}}{ \cancel{10}} \\ \\ \implies m = 30g \\ \\ So, \\ melted \: \: mass \: \: of \: \: ice \: \: in \: \: 5 \: \: mins \\ will \: \: be \: \: given \: \: by \implies \\ \\ \huge \boxed{ m = 30 \times 5 = 150g}$