Tinu takes 9 days more than his father to do certain work. Together they can do the work in 6 days. How many days will Tinu take to do that work alone
Answers
Tinu will take 18 days to complete the job alone
Step-by-step explanation:
Let the no of days taken by Tinu’s father be x
The no. of days taken by Tinu is (x + 9) days.
They complete the work in 6 days.
The amount of work done each day by them is 1/x+ 1/(x+9)= 1/6
((x+9)+x)/(x^2+9x)= 1/6
12 x+54 = x^2+9x
0 = x^2-3x-54
0 = x^2-9x+6x-54
0 = x (x-9)+ 6 (x-9)
0 = (x-9) (x+ 6)
Thus, x = 9 or x = -6
As the number of days cannot be negative, x = 9
The number of days take by Tinu’s father is 9 days.
Tinu takes (x +9) days, i.e., 18 days to complete the job alone
Answer:
Tinu will take 18 days to complete the job alone
Step-by-step explanation:
Let the no of days taken by Tinu’s father be x
The no. of days taken by Tinu is (x + 9) days.
They complete the work in 6 days.
The amount of work done each day by them is 1/x+ 1/(x+9)= 1/6
((x+9)+x)/(x^2+9x)= 1/6
12 x+54 = x^2+9x
0 = x^2-3x-54
0 = x^2-9x+6x-54
0 = x (x-9)+ 6 (x-9)
0 = (x-9) (x+ 6)
Thus, x = 9 or x = -6
As the number of days cannot be negative, x = 9
The number of days take by Tinu’s father is 9 days.
Tinu takes (x +9) days, i.e., 18 days to complete the job alone