8 cot θ =15 , Evalaute : (2 +2sinθ)(1 - sin θ) / (1 + cosθ) (2 -2 cos θ) yar koi to solve kardo plz
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Given that Tan(cos inverse of x ) = sin (cos inverse of 1/2) i.e sin ( cos inverse of 1/2) = sin (sin inverse of pie ‑ 1/2) = pie by 2 Therefore Tan (cos inverse of x) = pie by 2 Cos inverse of x = tan inverse of pie by 2 We know that tan inverse of pie by 2 =0 Therefore cos inverse of x =0 i.e, x=pie by 2
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