8.
The figure shows the positions and velocities of two particles. If the particles move under the mutual
of each other, then the position of centre of mass at t =1 s is :-
(A) x=5 m (B) x=6 m
(C) x=3 m
(D) x=2 m
horizontal plane ly along the x-axis, at a certain height
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Given :
•Time period =1 second.
x=2m •______________________•x=8m
•m1=1kg , v1=5m/s
•m2=1kg ,v2=3m/s
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To Find :
• The position of centre of mass at t=1 sec =?
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Solution :
➡ No other force is applied on the two particles system therefore their centre of mass position is at
After 1 second center of mass move 1m right
new center of mass at =5+1=6 m
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