Question

9. A body moving along a
straight line at 20 m/s
under goes an acceleration
4m/s^2 After 2s its speed will*
be​

Answer 1

Answer:

Explanation:

Solution,

Here, we have

Initial velocity of body, u = 20 m/s

Acceleration of body, a = 4 m/s²

Time taken by the body, t = 2 seconds

To Find,

Final velocity of body, v = ?

According to the 1st equation of motion,

We know that,

v = u + at

So, putting all the values, we get

v = u + at

⇒ v = 20 + 4 × 2

⇒ v = 20 + 8

⇒ v = 28 m/s

Hence, the final velocity of the body is 28 m/s.

Answer 2

Answer:

28 m/s

Explanation:

Given :

• Initial velocity of the body = u = 20 m/s
• Acceleration of the body = a = 4 m/s²
• Time accelerated for = t = 2 seconds

To find :

• Final velocity of the body after 2 seconds

Using the first equation of motion :V=u+at

V=20+4×2

V=20+8

V=28

The velocity of the body after 2 seconds is equal to 28 m/s