Question

9. At a temperature of 25°C, a steel rod has a length of 10m. What will be the increase in
length if temperature is raised to 35°C? ( = 1.1 x 10-5k ?)
(a) 11 x 10-3 m
(b) 1.1 x 103 m
(c) 111,1 x 103 m
(d) 11111 01.3 m​

Answer 1

Explanation:

∆t =35-25 = 10℃

change in length ∆l =

1.1*10^-5 *10 * ∆t = 1.1*10^-5 *10 * 10

= 1.1*10^-3 m

Answer 2

The correct answer is = 1.1*$10^{-3}$.

Given: Initial temperature = 25°C.

Final temperature = 35°C.

Constant = $1.1*10^{-5}$ k.

Length = 10m.

To Find: Increase in length.

Solution:

L = $L_{o}$(1-k*ΔT)

ΔL = $L_{o}$*k*  ΔT

Put the values in formula

= 10*  $1.1*10^{-5}$ *(35-25)

= 1.1*$10^{-3}$

Hence the change in length is = 1.1*$10^{-3}$.

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