A 0.60-kg book slides on a horizontal table. The kinetic friction force on the book has magnitude 1.5 n .
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Hey mate,
You posted an incomplete question.
◆ Complete question is-
0.60 kg book slides on a horizontal table. The kinetic friction force on the book has magnitude 1.3 N. How much work is done on the book by friction during a displacement of 3.3 m ?
◆ Answer-
Work done = 4.95 J
◆ Explanation-
# Given-
m = 0.6 kg
F = 1.5 N
s = 3.3 m
# Solution-
Work done by kinetic friction force is -
W = F.s
W = 1.5 × 3.3
W = 4.95 J
Therefore, work done in moving book is 4.95 J.
Hope it helps...
You posted an incomplete question.
◆ Complete question is-
0.60 kg book slides on a horizontal table. The kinetic friction force on the book has magnitude 1.3 N. How much work is done on the book by friction during a displacement of 3.3 m ?
◆ Answer-
Work done = 4.95 J
◆ Explanation-
# Given-
m = 0.6 kg
F = 1.5 N
s = 3.3 m
# Solution-
Work done by kinetic friction force is -
W = F.s
W = 1.5 × 3.3
W = 4.95 J
Therefore, work done in moving book is 4.95 J.
Hope it helps...
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