a 100g mixture of feo and fe2o3 gains 8g upon reaction with o2. calculate % by mass of fe2o3 in original 100g mixture.
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Answer:
Explanation:
Weight of fe2o3 - weight of feo =8
Moles of fe2o3 = moles of feo
X gm feo
W=1.45x
X=17.78 gm
Weight of fe2o3 = 82.23 gm
Percentage fe2o3 = 82.23
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