Question

A 30 kg boulder was initially moving at a velocity of 10 m/s, in order to stop it 10 N of
constant retarding force is applied on it. After how long will the boulder stop?​

Answer 1

Answer:

Given, m = 30 kg.

Retarding force = -10N

u = 10 m/s

v = 0.

We know, F = ma

-10 = 30 x a

a = -1/3 ms-2

Also, v = u + at

0 = 10 – t/3

Therefore, t = -10 x (-3)

= 30 s.

Answer 2

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❥ Solution

Answer:

Given, m = 30 kg.

Retarding force = -10N

u = 10 m/s

v = 0.

We know, F = ma

-10 = 30 x a

a = -1/3 ms-2

Also, v = u + at

0 = 10 – t/3

Therefore, t = -10 x (-3)

= 30 s.

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