Question

A 5.0cm long object is placed at a distance of 20cm from a convex lens of focal length 10cm object is placed normal to the principal axis of the lens. Find out,nature, position and size of the image

Answer 1

Answer:

Real and inverted between f and c 20/3

Answer 2

The image formed behind the lens and image will be virtual.

The height of the image is 5.0 cm

Explanation:

Given that,

Object distance = 20 cm

Focal length = 10 cm

Height of object = 5.0 cm

We need to calculate the image distance

Using formula of lens

$\dfrac{1}{f}=\dfrac{1}{v}-\dfrac{1}{u}$

Put the value into the formula

$\dfrac{1}{10}=\dfrac{1}{v}-\dfrac{1}{-20}$

$\dfrac{1}{v}=\dfrac{1}{10}-\dfrac{1}{20}$

$v=20\ cm$

We need to calculate the height of the image

Using formula of magnification

$m=\dfrac{v}{u}=\dfrac{h'}{h}$

Put the value into the formula

$\dfrac{20}{20}=\dfrac{h'}{5.0}$

$h'=5.0\cm$

Hence, The image formed behind the lens and image will be virtual.

The height of the image is 5.0 cm

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Topic : optics

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