Question

(a) A force ‘P’ of 235 N acts at an angle of

60º with the horizontal on a block resting

on a 30º inclined plane. Determine

algebraically : 7

(i) Horizontal and vertical components

of ‘P’

(ii) Components of ‘P’ perpendicular to

and along the plane.

(b) Two forces ‘P’ and ‘Q’ acting on a particle

at an angle ‘’ have a resultant

  2 2 2 1 P Q n   . When they act at an

angle of 90º–, the resultant becomes

  2 2 2 1 P Q n   . Show that 1

tan

1

n

n

 

 .

​

Answer 1

Answer:

Question poora karo pehli baat

and answer will be in front of you just draw the diagram ...

Step-by-step explanation:

30+60

force is at 90° with the plane

make the Cos n Sine components

that's it