A and b are two candidates seeking admission in a college .the probability that a is selected is 0.7 and probability that exactly one of them is selected is 0.6 .find the probability that only one of them is selected
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The probability that A is selected is 0.7, So the probability that B is selected will be (1-0.7=0.3).Therefore the probability that exactly one of them is selected is A
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Answer:
Probability that only one of them is selected = 0.825
Step-by-step explanation:
P(A) = 0.7
Let P(B) = p
the probability that exactly one of them is selected is 0.6
⇒ A is selected and B is not selected OR B is selected and B is not selected = 0.6
⇒ P(A)[1 - p] + p[1 - P(A)] = 0.6
⇒ 0.7 - 0.7p + p - 0.7p = 0.6
⇒ 0.4p = 0.1
⇒ p = 0.25
⇒ P(B) = 0.25
Therefore, The probability that B is selected = 0.25
Now, Probability that only one of them is selected = 1 - Probability that both of them is selected
⇒ Probability that only one of them is selected = 1 - 0.25 × 0.7
⇒ Probability that only one of them is selected = 0.825
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