A and b together can finish a piece of work in 12 days.if 'a' alone can finish the same work in 20 days , in how many days 'b' alone can finish it?
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a and b together do a work in 12 days; therefore a+b one day's work = 1/12
a alone can do in 20 days; therefore a's one day work =1/20
therefore from above we have '
a+b =1/12....(i) and a=1/20......(ii)
substituting the value of a in equation (i) we have
1/20+b =1/12
b=1/12-1/20
b=2/60
b=1/30
therefore in one day b does 1/30 part of work
therefore b alone can complete the whole work in 30 days
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