Math, asked by puja4thsaanno, 1 year ago

( a -b) 3 + ( b - c ) 3 + ( c - a ) 3 simplyfy

Answers

Answered by wolverine12
2
3a-3b+2b-3c+3c- 3a
=3a-3a+3c-3c+2b- 3b
=2b-3c
Answered by genious2000
0

( a -b) 3 + ( b - c ) 3 + ( c - a ) 3

= 3a - 3b + 3b -3c + 3c - 3a 9 (on multiplying  after opening brackets)

= 3a -3a + 3b -3b + 3c -3c (on rearranging)

=0

Similar questions