A bag contains 24 balls of which x are red 2x are white and 3x are blue. A ball is selectef randomly . What is the probability that is not white
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2x+x+3x=24. 6x=24.x=4. then red is 4 white are 8 and blue are 12. then no of ball except white=16 and no of total ball are 24 then pobabilty = 16/24=2/3
Answered by
1
Hey mate here is your answer:
Let the common factor be x, so
x+2x+3x=24.
6x=24.
x=24/6=4.
Now the no. of red balls=4.
The no. of white balls=8.
The no. of blue balls=12.
so the pribability that the ball is not white=(no. of red balls +no. of blue balls)/total no. of balls.
Probability=(12+4)/24=16/24=8/12=4/6=2/3.
Hope it helps you♥♥♥♥♥.
Let the common factor be x, so
x+2x+3x=24.
6x=24.
x=24/6=4.
Now the no. of red balls=4.
The no. of white balls=8.
The no. of blue balls=12.
so the pribability that the ball is not white=(no. of red balls +no. of blue balls)/total no. of balls.
Probability=(12+4)/24=16/24=8/12=4/6=2/3.
Hope it helps you♥♥♥♥♥.
sonal21200:
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