Question

A bag contains of One Rupee, 50 paisa and 25 paisa coins. If these coins are in the ratio of 2:3:10, and the total amount of money in the bag is Rs. 288, find the no of coins of 25 paisa

Answer 1

Answer:

Let number of one rupee coin be 2x

number of 50 paisa coin be 3x

number of 25 paisa coin be 10x

one rupee coin contains 2x*1 rupee

= Rs. 2x

50paisa coin contains 3x*50/100 rupee

=Rs. 3x/2

25 paisa coin contains 10x*25/100 rupee

=Rs. 5x/2

total amount of money = Rs. 288

or 2x +3x/2 + 5x/2. = 288

or 12x/2 = 288

or 6x = 288

or x = 288/6

or x = 48

number of coins of 25 paisa = 10*48 = 480