Physics, asked by Nidhi2002, 1 year ago

A ball is thrown vertically upward attains a maximum height of 45 m . The time after which velocity of the ball becomes equal to half the velocity of projection?


Nidhi2002: Plzzz give the solution

Answers

Answered by Disha27
13
v^2 =u^2+2as
0^2=u^2+2*(-10)*45
u^2=900
u= √900
u=30
taking v as 15,
we get
v=u+at
15=30+(-10*t)
15=30-10t
t=15/10= 3/2=1.5m/s
Similar questions