Question

A ball of mass 50g is dropped from a height of 10m it rebound losing 75% kinetic energy. If it remains in contact with the ground for t=0.01 sec the impulse of the impact force is

Answer 1

Mass=5×10^-2 kg.

t=10^-2 sec.

S(Displacement)=10 m.

S=ut+at^2 /2

2×10=0 +a(10^-4)

Hence, a= 2×10^5

Force= (5×10^-2) (2×10^5)

F=10^4 N

We know that,

Impulse =(Force).(time)

=(10^4) (10^-2)

= 10^2 N

(Hope it helps) :)