Question

A body dropped from the top of the tower reaches the ground in 4sec. Height of the tower is. (A)39.2 (B)44.1 (C)58.8 (D)78.4

Answer 1

S = u×t +1/2 g×t^2
As given that body is dropped
So, u = 0 m/s ,so u×t = 0
Now put value of t=4sec
S = 0 + 1/2 × 9.8× 4×4
S = 78.4 m

Answer 2

Explanation:

so. answer is 78.4 metre