A body has a weight 50 N in air. After immersing completely in liquid its weight is 20 N. Then the buoyant force on the body will be
Answers
Answered by
18
Actual weight of the body = 50N
and
when immeresed in water it's Boyant force + new weight = It's actual weight
Since, the new weight is 20N
Therefore,
the boyant force = 50N - 20N
Hence, the boyant force on the body will be 30N.
and
when immeresed in water it's Boyant force + new weight = It's actual weight
Since, the new weight is 20N
Therefore,
the boyant force = 50N - 20N
Hence, the boyant force on the body will be 30N.
Answered by
16
Hey!
_______________
We have,
Weight in air = 50 N
Weight in water = 20 N
Buoyant force applied = ?
We know,
Buoyant force + New weight = Actual weight
So, We have new weight = 20 N and actual weight = 50 N
Buoyant force + 20 = 50 N
Buoyant force = 50-20
Buoyant force = 30 N
________________
Hope it helps...!!!
_______________
We have,
Weight in air = 50 N
Weight in water = 20 N
Buoyant force applied = ?
We know,
Buoyant force + New weight = Actual weight
So, We have new weight = 20 N and actual weight = 50 N
Buoyant force + 20 = 50 N
Buoyant force = 50-20
Buoyant force = 30 N
________________
Hope it helps...!!!
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