Question

A body is moving with initial velocity of 20m/s on a rough surface. The velocity of the body decreases at the rate of 0.4m/s sq due to friction. After how much time will the body stop

Answer 1

u= 20m/s

v= 0m/s (as it stops)

a= -0.4m/s∧2

v=u+at

therefore, t= v-u/a

t= 0-20/ -0.4

t= -20/-0.4

therefore, t= 50s