A body of mass 1 kg is thrown vertically up with an initial direction of 5 ms, what is the magnitude and
direction of force due to gravity acting on the body when it is at its highest point? take g = 9.8 N kg
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mass =1kg
initial velocity =5m/s
final velocity =0m/s
g= -9.8Nkg
force = ma
= mg
= 1×-9.8=-9.8N
s=v^2-u^2/2g
= 0^2-5^2/2×-9.8
=25/196
=0.12755
Answered by
1
Answer:
Explanation:
F=ma
F=9.8*1
=9.8N downwards
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