A body of mass 5 kg has momentum 10 kg-m/s. When a force of 2 N acts for 10 seconds, then change in its kinetic energy will be
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Answer:
t=10sec
10=5×v[P=mv]
v=2m/s
As F=0.2N
a=
5
0.2
m/s
2
=
25
1
m/s
2
[a=
m
F
]
at t=0,KE=
2
1
×s×(2)
2
[KE=
2
1
mv
2
]
KE
i
=10J
Now, at t=10sec, v
f
=u+at
v
f
=g+
25
1
×10=2.4m/s
2
∴KE
f
=
2
1
×5×(2.4)
2
=14.4J
∴△KE=14.4−10
=4.4J
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