Physics, asked by krish513152, 5 months ago

A body of mass 5 kg has momentum 10 kg-m/s. When a force of 2 N acts for 10 seconds, then change in its kinetic energy will be​

Answers

Answered by neelamgarg091
0

Answer:

t=10sec

10=5×v[P=mv]

v=2m/s

As F=0.2N

a=

5

0.2

m/s

2

=

25

1

m/s

2

[a=

m

F

]

at t=0,KE=

2

1

×s×(2)

2

[KE=

2

1

mv

2

]

KE

i

=10J

Now, at t=10sec, v

f

=u+at

v

f

=g+

25

1

×10=2.4m/s

2

∴KE

f

=

2

1

×5×(2.4)

2

=14.4J

∴△KE=14.4−10

=4.4J

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