a body thrown vertically upward rises upto a height of 10m and come back to initial position. calculate
(a) the total distance travelled by a body
(b) displacement of the body
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Answered by
54
(a) The body goes up 10 m and therefore come down by 10 m. So total distance it travels is 10 m + 10 m = 20 m.
(b) Displacement is shortest distance between initial and final point. The body comes back to it initial point so its displacement = 0
(b) Displacement is shortest distance between initial and final point. The body comes back to it initial point so its displacement = 0
Answered by
23
Let's consider the initial position of body as A and final position of body as B.
If, the body goes from A to B and comes back from B to A , it's distance travelled will be →
2 × ( Distance between A and B) , as the body travels same path two times
So, distance travelled = 2 × 10m = 20m
As , the body comes back to it's initial position A , The distance between final and initial position is 0 , So the displacement is also 0.
If, the body goes from A to B and comes back from B to A , it's distance travelled will be →
2 × ( Distance between A and B) , as the body travels same path two times
So, distance travelled = 2 × 10m = 20m
As , the body comes back to it's initial position A , The distance between final and initial position is 0 , So the displacement is also 0.
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