a box of mass 40 kilogram is kept on a Floor .Sanjay is trying to push it from the left and Harish from the right.The forces exerted by them are 25 N and 35 N
However the box remains stationary.Find the force of friction acting on the box
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as net force is towards left which is equal to 10N and as block is at rest so frictional force is of equal magnitude and opposite to net force i.e. 10N towards right........
extra point from here you can also find coefficient of friction
10N=(mu)×normal force
10N=(mu)×400N
10/400=(mu)
(mu)=0.025
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