Question

a boy goes to market and an average speed of 29 kilometres finding the market close he returned backby the same path with an average speed of 40 kilometres find the average speed and average velocity of a complete journey​

Answer 1

Answer:

avg speed is 34.5 , avg velocity is 0

Explanation:

becoz avg speed = total distance/total time

avg velocity =total displacement/total time

so, speed =34.5

and avg velocity =0

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Answer 2

Answer:

1. Average Speed = 33.62 km/h
2. Average Velocity = 0km

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$\LARGE{\bf{\underline{\underline\color{blue}{Solution:-}}}}$

Distance = s in both case

1. T1 = s/v1 =s/29 h
2. T2=s/v2 =s/40 h

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$\sf\green{ </strong><strong>Average</strong><strong>\: </strong><strong>Speed</strong><strong> \:</strong><strong> </strong><strong>=</strong><strong> </strong><strong>}$

Average speed for whole trip = $\frac{ total \: \: distance }{ \:total \: \: time }$

= s+s/t1+t2

=2s km/ s/29+ s/40 h

=2s/69s/1160 km/h

=2× 1160/69

$\begin{gathered}\begin{gathered}: \implies \underline{ \boxed{\displaystyle \sf \bold{\:<strong>33.62 \: km/h</strong> }} }\\ \\\end{gathered}\end{gathered}$

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$\sf\green{ Average\: Velocity \: = }$

Displacement=0

T1=0/29 km/h

T2=0/40 km/h

Average velocity=displacement/time taken

Av=0/0/1160=0km/h because displacement is 0

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