Question

A bullet of mass 2 kg is havjng a charge of 2mc through what potential difference must it be accelerated starting from rest to aquire a speed of 10 m/s?(1). 5 kv(2). 50kv (3).5V (4).50V

Answer 1

Answer:

Explanation:

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Answer 2

Answer:

Potential difference,V = 50kv [Option(2)]

Explanation:

When a bullet of mass m and charge q is accelerated through potential difference of V volt, then it attains a kinetic energy equal to $qV.$

∴ kinetic energy of bullet =  $qV$

 →   $\frac{1}{2} m v^{2} = qV$

 →    $V = \frac{mv^2}{2q}$  ..................................................................(i)

Given, m =2g = $2*10^-3$ kg  ,q =2μC =2x $10^{-6}$ C  and  v = 10m/s

Putting this value in equation (i),we obtain

 $V = \frac{2 *10^{-3}* (10)^2}{2*2*10^-6} =\frac{200}{4* 10^{-3}}$

                            $= 50 * 10^3$ volt

                            = 50 kv [Ans]