sin(120)=?give me answer please
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Answered by
2
Here's the answer...........
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111Aslam:
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Answered by
1
Hey friend
Here is your answer
=sin(120°)
=sin(90°+30°)
[USING sin(A+B)=sinAcosB+cosAsinB]
=sin90°cos30°+cos90°sin30°
=[1×(√3/2)]+[0×(1/2)]
=√3/2
==============================
HOPE THIS HELPS YOU ☺
Here is your answer
=sin(120°)
=sin(90°+30°)
[USING sin(A+B)=sinAcosB+cosAsinB]
=sin90°cos30°+cos90°sin30°
=[1×(√3/2)]+[0×(1/2)]
=√3/2
==============================
HOPE THIS HELPS YOU ☺
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