A bullet of mass 50 gram moving with an initial velocity 100 m/s, strikes a wooden block and comes to rest after penetrating a distance 2 cm in it. calculate: (i)initial momentum of the bullet, (ii)final momentum of the bullet, (iii)retardation caused by the wooden block, and (iv)resistive force exerted by the wooden block.
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Coordinate for uniformly accelerated motion equals: = 0 −
2
2
0 - initial velocity of the bullet
–deceleration
− time
Velocity for uniformly accelerated motion equals:
= 0 −
If bullet comes to rest: = 0 => =
0
Therefore, from the equation for coordinate:
= 0
0
−
(
0
)
2
2
=
0
2
2
deceleration equals:
=
0
2
2
= (100
)
2
/2
And, finally, retardation equals:
= =
0
2
2
= 0.05 ∗
(100
)
2
2 ∗ 0.02
= 12500 = 12.5 Answer: 12500
rajo1:
Yaa thnxx.. I got it bt actually its not a graph based question, bt its okk.
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