Question

A bus covers a distance of 250 km from Delhi to Jaipur towards west in 5 hours.it returns to Delhi the same distance in 6 hours . find average velocity of bus in whole journey​

Answer 1

Solution :

(i) Average =

Total distance travelled

Total time taken

250 km + 250 km

5h + 5h

= 500km

10 h

= 50 km/h <br> Thus, the average speed of the bus fot the whole journey (both ways) is 50 kilometres per hour. <br> (ii) In this case, the bus travels 250 km from Delhi to Jaipur towards West and then comes back to starting point Delhi in the reverse direction. So, the total displacement (or total distance travelled in a specified direction) will be 250 km - 250 km = 0 km. Now, <br> Average velocity =

Total displacement

Total time taken

=

250

km

−

250

km

5

h

+

5

h

=

0

km

10

h

= 0 km/h <br> Thus, the average velocity of the bus for the whole journey (both ways) is 0 kilometres per hour. No direction can be stated in this case of zero velocity.

Answer 2

Given:

• Bus cover distance of 250km from Delhi to Jaipur in 5 hours
• On returning, same distance covered by bus is 6 hours

To find:

• Average velocity of bus in whole journey

Solution:

Given that bus is covering 250km distance in 5 during when it's going from Delhi to Jaipur.

According to find average velocity,

We know that ;

$\large{\sf{Average\: velocity\:=\: \dfrac{Displacement}{time}}}$

Now,

First we find Displacement covered by bus :-

∵ given that bus is traveling same distance from both sides.

Therefore,

• Displacement covered by bus will be 0.

Now, given that time taken by bus is 5 hours and 6 hours respectively in first and second journey.

Therefore,

• Time taken by bus is 5+6 = 11 hours.

Finding average velocity :

$\large{\sf{Average\: velocity\:=\: \dfrac{Displacement}{time}}}$

$\implies{\large{\sf{Average\: velocity\:=\:\dfrac{0}{11}}}}$

$\implies{\large{\sf{Average\: velocity\:=\:0}}}$