Question

A car accelerates uniformly from 18 Km/h to 36 Km/h in 5 second calculate : Acceleration and distance covered

Answer 1

Answer:

a=1m/s^2

s=37.5m/s

Explanation:

u=18kmph=5m/s

v=10m/s

From equation of motion

v=u+at

a=1m/s^2

From equation of motion

s=ut+1/2at^2

s=5×5+1/2×1×5^2

s=25+12.5

s=37.5 m

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Answer 2

Initial Velocity u = 18km/h = 18km/h * 5/18 = 5m/s

Final Velocity v  = 36km/h = 36km/h * 5/18 = 10m/s

• Acceleration = v-u /t

                    = (10m/s - 5m/s) / 5

                    = 5m/s / 5

                    = 1m/s^2