A car is moving with speed u driver of the car cigarette traffic light reaction time is t then find out the distance travelled by the car after the incident when driver decided to apply brakes assume uniform retardation after applying brakes
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During the duration of reaction and application of brake the car is still in uniform velocity..... So distance traveled will be
D1 = u * t
Later as deceleration is applied distance covered before coming to rest is
V^2 = u^2 + 2*a*D2 (here v = 0)
So total distance will be D1+D2
Answer is ut+u^2 /2a
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