A car moving along a straight line with speed of 126 km/h is brought to a stop within a distance of 200m.
What is ritardation of car and how long does it take for car to stop.
Answers
Answered by
2
Answer:
Stopping distance will be s = u×u/2a
From second equation of motion
Explanation:
Converting 126 km/hr in m/s
126×5/18
35 m/s
Now applying the above equation
200 = 35×35/ 2a
400 a = 35× 35
a = 1225/ 400
a = 3.06 m/s^2
Answered by
1
Explanation:
a =
..............3.06 m/s^2
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