A chord of a circle of a radius 28cm subtends a right angle at the centre. What is the area of the minor sector ? (π= 227)
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Answer:
the area of sector = theta/360° x πr²
r = 28cm (given)
theta = 90° (given)
Area = 90/360 x 22/7 x 28 x 28
=>1 x 11 x 4 x 14 = 11 x 56
= 616cm²
therefore, area of sector = 616cm²
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