Question

A chord of circle of radius 10cm subtend an angle 90 degrees at centre. find the area of the minor sector

Answer 1

Radius of circle
r(sqrt 2) = 10
r=10/sqrt2
                             Area of minor sector will be = 1/4*3.14*10/sqrt2
                                                                         = 39.25 cm^2

Answer 2

Answer:

Step-by-step explanation:

Area of minor sector = Teta/360 into pi into r into r

Now,

90/360 into 22/7 into 10 into 10 =78.54 cm sqr.

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