Physics, asked by emmajesusco, 1 year ago

A conductor possesses a positive charge of 3.2x 10-19 C. How many electron
does it have in excess or deficit (e = 1.60 x 10-19C)

Answers

Answered by saltywhitehorse
31

Given charge on one electron = -1.6\times10^{(-19)}\text{ C}

Conductor possesses a positive charge of =3.2\times10^{(-19)}\text{ C}

Therefore,

No. of electrons = \frac{3.2\times10^{-19}}{1.6\times10^{-19}} = \frac{3.2}{1.6} =2

Since the charge on the conductor is positive, the conductor is 2 electrons short.

Answered by vikaspattanshetti1
2

Answer:

1.60*10-19C so the charge is..

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