Question

A conductor possesses a positive charge of 3.2x 10-19 C. How many electron
does it have in excess or deficit (e = 1.60 x 10-19C)

Answer 1

Given charge on one electron = $-1.6\times10^{(-19)}\text{ C}$

Conductor possesses a positive charge of $=3.2\times10^{(-19)}\text{ C}$

Therefore,

No. of electrons = $\frac{3.2\times10^{-19}}{1.6\times10^{-19}} = \frac{3.2}{1.6} =2$

Since the charge on the conductor is positive, the conductor is 2 electrons short.

Answer 2

Answer:

1.60*10-19C so the charge is..