a cone is 8.4cm high and the radius of its base is 2.1 cm . it is melted to form a sphere . find the radius of the sphere.
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RADIUS OF CONE= 2.1CM
HEIGHT OF THE CONE= 8.4CM
RADIUS OF SPHERE = R
WE KNOW THAT VOLUMES DOES'NT CHANGE WHEN SOME SHAPE IS MELTED AND CONVERTED TO OTHER.
SO, VOLUME OF CONE= VOLUME OF SPHERE
[tex]R^{3} = \frac{(2.1)^2(8.4)}{4} = \frac{4.41*8.4}{4} = 9.261 =\sqrt[3]{9.261} = 2.1CM[/tex]
THE RADIUS OF SPHERE = 2.1 CM
HOPE THIS HELPS........
HEIGHT OF THE CONE= 8.4CM
RADIUS OF SPHERE = R
WE KNOW THAT VOLUMES DOES'NT CHANGE WHEN SOME SHAPE IS MELTED AND CONVERTED TO OTHER.
SO, VOLUME OF CONE= VOLUME OF SPHERE
[tex]R^{3} = \frac{(2.1)^2(8.4)}{4} = \frac{4.41*8.4}{4} = 9.261 =\sqrt[3]{9.261} = 2.1CM[/tex]
THE RADIUS OF SPHERE = 2.1 CM
HOPE THIS HELPS........
vaniR:
Thanks a lot for marking as brainliest answer :)
Answered by
1
HI there !!
Height = h = 8.4 cm
Radius = r = 2.1 cm
Volume of cone = 1/3πr²h
Volume of the cone = Volume of new sphere
Volume of new sphere = 4/3πr³
4/3πr³ = 1/3πr²h
4/3 × 22/7 × r³ = 1/3 × 22/7 × 2.1 × 2.1 × 8.4
4 r ³ = 2.1 × 2.1 × 8.4
r ³ = [ 2.1 × 2.1 × 8.4 ] ÷ 4
r³ = 9.261
r = ∛ 9.261
r = 2.1 cm
Height = h = 8.4 cm
Radius = r = 2.1 cm
Volume of cone = 1/3πr²h
Volume of the cone = Volume of new sphere
Volume of new sphere = 4/3πr³
4/3πr³ = 1/3πr²h
4/3 × 22/7 × r³ = 1/3 × 22/7 × 2.1 × 2.1 × 8.4
4 r ³ = 2.1 × 2.1 × 8.4
r ³ = [ 2.1 × 2.1 × 8.4 ] ÷ 4
r³ = 9.261
r = ∛ 9.261
r = 2.1 cm
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