A conical tent has an angle of 60 degree at the vertex . if the curved surface area is 100 meter square. then the volume of the tent is.
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Step-by-step explanation:
Given A conical tent has an angle of 60 degree at the vertex . if the curved surface area is 100 meter square. then the volume of the tent is
- Curved surface area of a cone is = π r l
- = π r (r^2 + h^2)
- We need to find r
- So tan 60 = r / h
- √3 = r / h
- Or r = h√3
- Now curved surface area of cone = π √3 h √(√3 h)^2 + h^2)
- 100 = π √3 h (√3 h^2 + h^2)
- 100 = π √3 h x 2h
- 100 = 2 √3 π h^2
- 100 / 2 √3 π = h^2
- So h = √700 / 76.21
- Or h = 3.03 m^2
- Now volume of cone = 1/3 π r^2 h
- = 1/3 x 22 / 7 x (3√3)^2 x 3.03
- = 1799.82 / 21
- = 85.70 m^3
- So volume of the conical tent is 85.70 m^3
Reference link will be
https://brainly.in/question/5553233
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