Question

a cricket ball of mass 200 gram is moving with the velocity 15 M per second is brought to rest by a player in 0.05 seconds the average force exerted by a player is

Answer 1

$a = \frac{ 0- 15}{0.05} = - 300m \: per \: {second}^{2} \\ now \: mass \: = 0.2kg \\ f = m \times a \\ f = - 300 \times 0.2 = - 60 \: newtons$

Answer 2

m=200mg or 0.2 kg
v= 15m/s
t=0.05s
we know that F=ma
so,F=0.2*v/t
F=0.2*15/0.05=60N