Question

A cube of 4 cm has been
painted on its surfaces in such
a way that two opposite
surfaces have been painted
blue and two adjacent surfaces
have been painted red. Two
remaining surfaces have been
left unpainted. Now the cube is
cut into smaller cubes of side 1
cm each. How many cubes will
have at least blue colour on its
surfaces ?
​

Answer 1

Answer:

28

Step-by-step explanation:

Two adjacent surfaces have been painted red and if cut these surface into 1 cm length then we would get many small cube of side 1 cm, and so one surface of big cube will form 4∗4=16 surfaces of small cube. 

Now as per given statement in question, "two adjacent surfaces have been painted red" That means adjacent surface will also form 4∗4=16 small cube with red paint. 

So total cube of red colour might be 16+16=32 . 

But the four cubes are common in both the red colour surfaces.

Thus, total cubes having at least red colour on its surfaces will be 32−4=28.