A cube of side 28 cm has four identical solid spheres tightly fitted into it. Approximately how much water can be filled in this cube? (= 22/7)
Answers
Given info : A cube of side 28 cm has four identical solid spheres tightly fitted into it.
To find : how much water can be filled in this cube ?
solution : see figure,
diameter of sphere = half of side length of the cube.
⇒ 2r = 28/2 = 14
⇒r = 7 cm
so, volume of four sphere = 4 × 4/3 πr³
= 4 × 4/3 × 22/7 × 7 × 7 × 7
= 16/3 × 22 × 49
= 5,749.3 cm³
volume of cube = (28 cm)³
= 21952 cm³
the volume of water can be filled in the cube = volume of cube - volume of four spheres
= 21952 - 5749.3
= 16202.7 cm³
Therefore the volume of water is 16202.7 cm³ that can be filled in the cube.
Answer:-
Given info :
A cube of side 28 cm has four identical solid spheres tightly fitted into it.
To find :
how much water can be filled in this cube ?
solution :
see figure,
diameter of sphere = half of side length of the cube.
⇒ 2r = 28/2 = 14
⇒r = 7 cm
so, volume of four sphere = 4 × 4/3 πr³
= 4 × 4/3 × 22/7 × 7 × 7 × 7
= 16/3 × 22 × 49
= 5,749.3 cm³
volume of cube = (28 cm)³
= 21952 cm³
the volume of water can be filled in the cube = volume of cube - volume of four spheres
= 21952 - 5749.3
= 16202.7 cm³
Therefore the volume of water is 16202.7 cm³ that can be filled in the cube.
Hope it's help you❤️