Question

Solve this!!..............​

Answer 1

GIVEN :-

• Mass = 250 g
• Speed = 2 m/s
• Time of contact = 10⁻³ sec
• The average force exerted by the wall on the ball = ?

━━━━━━━━━━━━━━

$\begin{gathered}:\implies \sf{ \Delta p = mv + mv}\\\\\end{gathered}$

$\begin{gathered}:\implies \sf{ \Delta p = 2(mv)}\\\\\end{gathered}$

Now we shall find the average force!!

$\begin{gathered}:\implies \sf{F = \dfrac{dp}{dt} }\\\\\end{gathered}$

$\begin{gathered}:\implies \sf{F = \dfrac{\Delta p}{\Delta t} }\\\\\end{gathered}$

$\begin{gathered}:\implies \sf{F = \dfrac{2mv}{\Delta t} }\\\\\end{gathered}$

$\begin{gathered}:\implies \sf{F = \dfrac{2 \times 0.25 \times 2}{ {10}^{ - 3}} }\\\\\end{gathered}$

$\begin{gathered}:\implies \sf F = \dfrac{2 \times 250 \times 10^{-3} \times 2}{ {10}^{ - 3}} \\\\\end{gathered}$

$\begin{gathered}:\implies \sf F = \dfrac{1000\times \cancel{10^{-3}}}{\cancel{{10}^{ - 3}}} \\\\\end{gathered}$

$:\implies \underline{\boxed{\mathfrak{\pink{ f = 1000 \: n}}}}$

Answer 2

Answer:

GIVEN :-

Mass = 250 g

Speed = 2 m/s

Time of contact = 10⁻³ sec

The average force exerted by the wall on the ball = ?

━━━━━━━━━━━━━━

\begin{gathered}\begin{gathered}:\implies \sf{ \Delta p = mv + mv}\\\\\end{gathered}\end{gathered}

:⟹Δp=mv+mv

\begin{gathered}\begin{gathered}:\implies \sf{ \Delta p = 2(mv)}\\\\\end{gathered}\end{gathered}

:⟹Δp=2(mv)

Now we shall find the average force!!

\begin{gathered}\begin{gathered}:\implies \sf{F = \dfrac{dp}{dt} }\\\\\end{gathered}\end{gathered}

:⟹F=

dt

dp

\begin{gathered}\begin{gathered}:\implies \sf{F = \dfrac{\Delta p}{\Delta t} }\\\\\end{gathered}\end{gathered}

:⟹F=

Δt

Δp

\begin{gathered}\begin{gathered}:\implies \sf{F = \dfrac{2mv}{\Delta t} }\\\\\end{gathered}\end{gathered}

:⟹F=

Δt

2mv

\begin{gathered}\begin{gathered}:\implies \sf{F = \dfrac{2 \times 0.25 \times 2}{ {10}^{ - 3}} }\\\\\end{gathered}\end{gathered}

:⟹F=

10

−3

2×0.25×2

\begin{gathered}\begin{gathered}:\implies \sf F = \dfrac{2 \times 250 \times 10^{-3} \times 2}{ {10}^{ - 3}} \\\\\end{gathered}\end{gathered}

:⟹F=

10

−3

2×250×10

−3

×2

\begin{gathered}\begin{gathered}:\implies \sf F = \dfrac{1000\times \cancel{10^{-3}}}{\cancel{{10}^{ - 3}}} \\\\\end{gathered}\end{gathered}

:⟹F=

10

−3

1000×

10

−3

:\implies \underline{\boxed{\mathfrak{\pink{ f = 1000 \: n}}}}:⟹

f=1000n